Classes of IP Addresses
Sample Quiz
Will these IP's require a router to talk to each other? This is another way of asking are these hosts on the same network or subnet?
Given 192.168.1.0/ 24
Host a: 192.168.1.33/ 27
Host b: 192.168.1.50/ 28
Host c: 192.168.1.100/ 26
Host d: 192.168.1.90/ 27
There are whole chapters in books dedicated to subnetting. This can be easily simplified into two rows of numbers; it would be a very short book if I was writing it. This is like subnetting in your brain!
Write this down:
128 64 32 16 8 4 2 1
128 192 224 240 248 252 254 255
Start with Host a 192.168.1.33
/ 27 mask means a mask of 255.255.255.224
Then valid networks are 0, 32, 64, etc *
Network address would be .32
Valid hosts would be .33 to 62
Broadcast address would be .63
The number of subnets 2^3 = 8 where 3 is the number of masked bits or 1s
The number of hosts in each subnet 2^5 -2 = 30
* Finding the subnet base number
256 - mask = base number
Host b 192.168.1.50
/28 means a mask of 255.255.255.240
The valid networks would be 0, 16, 32, 48, 64 etc
Network address would be .48
Valid hosts would be .49 to 62
Broadcast address would be .63
Host c 192.168.1.100
/26 means a mask of 255.255.255.192
The valid networks are 0, 64, 128 etc
Network address is .64
Valid hosts .65 to 126
Broadcast .127
Host d 192.168.1.90
/27 mask means 255.255.255.224
Valid networks 0, 32, 64, 96
Network address is .64
Valid hosts .65 to .94
Broadcast .95
Answer, no body can talk to each other because they're on different subnets (different network addresses). A router would be required.
Binary Quiz
Convert 452 into binary
answer: 111000100
What is 11000111?
answer: 199
Convert 11101000111 into decimal
answer: 1863
A Class A network has 3 octets for the host field.
What is the practical minimum number of bits to borrow? 2
Using six subnet bits, how many usual subnets are created?
62
How many subnet bits do you borrow?
To see how many bits you should borrow from the host portion of the network address to give the required number of subnets, you should...
answer: substract the number of subnets you need from the network portion
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